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Let f: R - \0\ (- , 1) be a polynomial of degree 2, satisfying f(x)f ( 1x ) = f(x) + f ( 1x ). If f(K) = -2K, then the sum of squares of all possible values of K is:
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JEE Main 2025 (Online) 28th January Evening Shift
Previous year questions with solutions · 2025 – 2026
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|---|---|---|---|---|
| 2026 | 20 | 19 | 1.1 | 4.21% ↓21.1% |
| 2025 | 16 | 12 | 1.3 | 5.33% |
Let f: R - \0\ (- , 1) be a polynomial of degree 2, satisfying f(x)f ( 1x ) = f(x) + f ( 1x ). If f(K) = -2K, then the sum of squares of all possible values of K is:
Let f : [0, 3] A be defined by f(x) = 2x3 - 15x2 + 36x + 7 and g : [0, ) B be defined by g(x) = x2025x2025 + 1. If both the functions are onto and S = \x Z; x A or x B\, then n(S) is equal to :