A simple pendulum made of mass 10 g and a metallic wire of length 10 cm is suspended vertically in a uniform magnetic field of 2 T. The magnetic field direction is perpendicular to the plane of oscillations of the pendulum. If the pendulum is released from an angle of 60 with vertical, then maximum induced EMF between the point of suspension and point of oscillation is mV. (Take g = 10 m/s2)
Electromagnetic Induction
Previous year questions with solutions · 2025 – 2026
25Questions
16Papers covered
4% ↑100%Weightage in 2026
’25
’26
Year-wise statistics questions · papers · average per paper · weightage
| Year | Questions | Papers | Avg / paper | Weightage |
|---|---|---|---|---|
| 2026 | 19 | 19 | 1 | 4.00% ↑100% |
| 2025 | 6 | 12 | 0.5 | 2.00% |
1
JEE Main 2026 (Online) 23rd January Morning Shift
2
Conductor wire ABCDE with each arm 10 cm in length is placed in magnetic field of 1 2 Tesla, perpendicular to its plane. When conductor is pulled towards right with constant velocity of 10 cm/s, induced emf between points A and E is mV. [figure]
JEE Main 2025 (Online) 4th April Morning Shift
3
[figure] A conducting bar moves on two conducting rails as shown in the figure. A constant magnetic field B exists into the page. The bar starts to move from the vertex at time t = 0 with a constant velocity. If the induced EMF is E tn, then value of n is .
JEE Main 2025 (Online) 28th January Evening Shift