Conductor wire ABCDE with each arm 10 cm in length is placed in magnetic field of 1 2 Tesla, perpendicular to its plane. When conductor is pulled towards right with constant velocity of 10 cm/s, induced emf between points A and E is mV. [figure]
Answer
10
Solution
Motional emf across a conductor of any shape: = Bv leff, where leff is the length of the conductor perpendicular to v (the projection of AE perpendicular to the velocity).
AB and DE are parallel to v no emf in them.
BC and CD each make 45 with v (angle BCD = 90 , symmetric about the velocity):
leff = 10 45 + 10 45 = 10 2 cm = 0.1 2 m
= 1 2 0.1 0.1 2
= 0.01 V = 10 mV
Answer: 10