Water falls from a height of 200 m into a pool. Calculate the rise in temperature of the water assuming no heat dissipation from the water in the pool. (Take g = 10 m/s2, specific heat of water = 4200 J/(kg K))
- 0.36 K
- 0.23 K
- 0.48 K
- 0.14 K
Answer
(3) 0.48 K
Solution
The whole potential energy lost by the water is converted into heat in the water:
mgh = ms T
T = ghs = 10 2004200
= 0.476 K 0.48 K
Answer: (3)