The difference in the capacitance (in F) between the metal plates at t=0 and that at t=500 s is (8-n) 0, where 0 is the permittivity of free space. The value of n is:
Answer
1.90 to 2.10
Solution
Key idea: each chamber (area 1 m2, gap 2 m) is a liquid layer h in series with air (2-h): C= 0Ah/ r+(2-h); the outside region is unchanged and cancels in the difference.
t=0: left = 02/15=7.5 0, right = 02=0.5 0; total 8 0.
t=500 s (h1=1.25, h2=0.75): left = 01.25/15+0.75=1.2 0, right = 00.75/15+1.25= 01.3=0.769 0.
C=8 0-1.969 0=(8-n) 0 n 1.97.
Answer: 1.97 (accepted range 1.90 to 2.10)