Suppose a uniformly charged wall provides a uniform electric field of 2 104 N/C normally. A charged particle of mass 2 g being suspended through a silk thread of length 20 cm and remain stayed at a distance of 10 cm from the wall. Then the charge on the particle will be 1 x μC where x= . [use g=10 m/s2]
Answer
3
Solution
[figure]
= 1020= 12 =30
Equilibrium: T =mg, T =qE = qEmg
q= mg 30 E= 2 10-3 10 3 2 104
= 1 3 10-6 C= 1 3
x=3
Answer: 3