Two spherical bodies of same materials having radii 0.2 m and 0.8 m are placed in same atmosphere. The temperature of the smaller body is 800 K and temperature of the bigger body is 400 K . If the energy radiated from the smaller body is E, the energy radiated from the bigger body is (assume, effect of the surrounding temperature to be negligible),
- 64 E
- 16 E
- E
- 256 E
Answer
(3) E
Solution
Stefan's law: E AT4 r2T4 (same material, same time).
E'E= ( 0.80.2 )2 ( 400800 )4=16 116=1
E'=E
Answer: (3)