The radiation pressure exerted by a 450 W light source on a perfectly reflecting surface placed 2 m away from it, is
- 3 10-8 Pascals
- 0
- 1.5 10-8 Pascals
- 6 10-8 Pascals
Answer
(4) 6 10-8 Pascals
Solution
The source radiates uniformly in all directions, so the intensity at r = 2 m is
I = P4 r2 = 4504 4 8.95 W m-2
For a perfectly reflecting surface (normal incidence): p = 2Ic
= 2 8.953 108 6 10-8 Pa
Answer: (4)