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Electric Charges and Fields · Question 24

JEE Main 2025 (Online) 29th January Morning ShiftMCQMedium📈 Topic in 13% papers+4−1
1

An electric dipole of mass m, charge q, and length l is placed in a uniform electric field E = E0 i. When the dipole is rotated slightly from its equilibrium position and released, the time period of its oscillations will be :

  1. 12 ml2qE0
  2. 2 ml2qE0
  3. 2 mlqE0
  4. 12 2mlqE0

Answer

(2) 2 ml2qE0

Solution

The dipole consists of two charged particles +q and -q, each of mass m, at a distance l2 from the centre.

Moment of inertia about the centre: I = 2m ( l2 )2 = ml22

Dipole moment: p = ql

For a small angular displacement : = -pE0 -qlE0

I d2 dt2 = -qlE0 (angular SHM)

2 = qlE0I = qlE0ml2/2 = 2qE0ml

T = 2 = 2 ml2qE0

Answer: (2)

JEE Main 2025 (Online) 29th January Morning Shift

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2

Match List - I with List - II. Choose the correct answer from the options given below :

  1. (A)-(IV), (B)-(I), (C)-(III), (D)-(II)
  2. (A)-(II), (B)-(I), (C)-(IV), (D)-(III)
  3. (A)-(III), (B)-(II), (C)-(IV), (D)-(I)
  4. (A)-(IV), (B)-(II), (C)-(III), (D)-(I)
JEE Main 2025 (Online) 29th January Morning Shift

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