29082X Y e+ Z - P e- Q In the nuclear emission stated above, the mass number and atomic number of the product Q respectively, are
- 280, 81
- 286, 80
- 288, 82
- 286, 81
Answer
(4) 286, 81
Solution
-emission: A decreases by 4, Z by 2
Y: A = 286, Z = 80
e+ ( +) emission: Z decreases by 1
Z: A = 286, Z = 79
- emission: Z increases by 1
P: A = 286, Z = 80
e- ( -) emission: Z increases by 1
Q: A = 286, Z = 81
Answer: (4)