Ques. 1JEE Main 2024, 29 January (Evening Shift)
A particle is moving in a straight line. The variation of position 'x' as a function of time 't' is given as x= (t3-6t2+20t+15 )m. The velocity of the body when its acceleration becomes zero is :
- 6 m/s
- 10 m/s
- 8 m/s
- 4 m/s
Answer
(3) 8 m/s
Solution
v= dxdt=3t2-12t+20, a= dvdt=6t-12
a=0 t=2 s
v=3(2)2-12(2)+20=12-24+20=8 m/s
Velocity and acceleration are the first and second time-derivatives of position.
Answer: (3)