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System of Particles and Rotational Motion · Question 6

JEE Advanced 2024 Paper 1NumericalHard📈 Topic in 17% papers+4
1

A disc of mass M and radius R is free to rotate about its vertical axis as shown in the figure. A battery operated motor of negligible mass is fixed to this disc at a point on its circumference. Another disc of the same mass M and radius R/2 is fixed to the motor's thin shaft. Initially, both the discs are at rest. The motor is switched on so that the smaller disc rotates at a uniform angular speed . If the angular speed at which the large disc rotates is /n, then the value of n is . [figure]

Answer

12

Solution

Key idea: motor torques are internal; no external torque about the fixed vertical axis of the large disc ⇒ angular momentum about it stays zero.

Let the large disc turn with (one sense) and the small disc spin with (ground frame, opposite sense).

Large disc: L1= MR22 . Small disc's centre moves on a circle of radius R: orbital part MR2 .

Spin of small disc: M(R/2)22 = MR28 .

MR22 +MR2 = MR28 ⇒ = 12.

Answer: 12

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2

A thin uniform rod of length L and certain mass is kept on a frictionless horizontal table with a massless string of length L fixed to one end (top view is shown in the figure). The other end of the string is pivoted to a point O. If a horizontal impulse P is imparted to the rod at a distance x=L/n from the mid-point of the rod (see figure), then the rod and string revolve together around the point O, with the rod remaining aligned with the string. In such a case, the value of n is . [figure]

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3

If the collision occurs at time t0 = 0, the value of vcm/(a ) will be .

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