A biconvex lens has a radius of curvature of magnitude 20 cm. Which one of the following options best describes the image formed of an object of height 2 cm placed 30 cm from the lens ?
- Virtual, upright, height = 1 cm
- Virtual, upright, height = 0.5 cm
- Real, inverted, height = 4 cm
- Real, inverted, height = 1 cm
Answer
(3) Real, inverted, height = 4 cm
Solution
Taking the refractive index of the lens glass = 1.5:
1f = ( - 1) ( 1R1 - 1R2 ) = 0.5 ( 120 + 120 ) = 120
f = +20 cm
Lens formula with u = -30 cm:
1v = 1f + 1u = 120 - 130 = 160
v = +60 cm (real image)
m = vu = 60-30 = -2 (inverted)
Image height = 2 2 = 4 cm, real and inverted
Answer: (3)