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Gravitation · Question 14

JEE Main 2025 (Online) 3rd April Morning ShiftNumericalMedium📈 Topic in 6% papers+4
1

Three identical spheres of mass m are placed at the vertices of an equilateral triangle of length a. When released, they interact only through gravitational force and collide after a time T = 4 seconds. If the sides of the triangle are increased to length 2a and also the masses of the spheres are made 2 m, then they will collide after seconds.

Answer

8

Solution

The collapse time can depend only on G, m and a.

Acceleration of each sphere Gma2 and the distance to be covered a

t aGm/a2 = a3Gm

t'T = (2a)32m ma3 = 4 = 2

t' = 2 4 = 8 s

Answer: 8

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2

A satellite of mass 1000 kg is launched to revolve around the earth in an orbit at a height of 270 km from the earth's surface. Kinetic energy of the satellite in this orbit is 1010 J. (Mass of earth = 6 1024 kg, Radius of earth = 6.4 106 m, Gravitational constant = 6.67 10-11 N m2 kg-2)

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3

Earth has mass 8 times and radius 2 times that of a planet. If the escape velocity from the earth is 11.2 km/s, the escape velocity in km/s from the planet will be:

  1. 8.4
  2. 11.2
  3. 5.6
  4. 2.8
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