Two blocks with masses 100 g and 200 g are attached to the ends of springs A and B as shown in figure. The energy stored in A is E. The energy stored in B, when spring constants kA, kB of A and B, respectively satisfy the relation 4kA = 3kB, is : [figure]
- 4E
- 2E
- 43E
- 3E
Answer
(4) 3E
Solution
In equilibrium the spring force balances the weight: kx = mg x = mgk
Energy stored: U = 12kx2 = (mg)22k
UBUA = ( mBmA )2 kAkB = ( 200100 )2 34 = 3
UB = 3E
Answer: (4)