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Electromagnetic Induction · Question 36

AIPMT 2005MCQEasy📈 Topic in 25% papers+4−1
1

As a result of change in the magnetic flux linked to the closed loop as shown in the figure, an e.m.f. V volt is induced in the loop. The work done (joule) in taking a charge Q coulomb once along the loop is [figure]

  1. QV
  2. 2QV
  3. QV/2
  4. zero

Answer

(1) QV

Solution

As per NCERT, the induced emf is the work done per unit charge in moving it once around the closed loop (the induced electric field is non-conservative).

W = Q V = QV

Answer: (1)

AIPMT 2005

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2

A coil of 40 henry inductance is connected in series with a resistance of 8 ohm and the combination is joined to the terminals of a 2 volt battery. The time constant of the circuit is

  1. 5 seconds
  2. 1/5 seconds
  3. 40 seconds
  4. 20 seconds
AIPMT 2004
3

The magnetic flux through a circuit of resistance R changes by an amount in a time t. Then the total quantity of electric charge Q that passes any point in the circuit during the time t is represented by

  1. Q = 1R t
  2. Q = R
  3. Q = t
  4. Q = R t
AIPMT 2004
4

For a coil having L = 2 mH, current flow through it is I = t2e-t then, the time at which emf becomes zero

  1. 2 sec
  2. 1 sec
  3. 4 sec
  4. 3 sec
AIPMT 2001

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