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Thermodynamics (Physics)

JEE Main 2024 (Online) 29th January Morning ShiftMCQMedium📈 Topic in 5% papers+4−1
Ques. 1JEE Main 2024, 29 January (Morning Shift)

A thermodynamic system is taken from an original state A to an intermediate state B by a linear process as shown in the figure. Its volume is then reduced to the original value from B to C by an isobaric process. The total work done by the gas from A to B and B to C would be : [figure]

  1. 800 J
  2. 2200 J
  3. 33800 J
  4. 1200 J

Answer

(1) 800 J

Solution

[figure]

WAB+WBC = area of triangle ABC

WAB (expansion) = area under AB (+); WBC (compression) = - area under BC.

W= 12 (7-3) m3 (8000-4000) dyne/cm2

=8000 dyne cm-2 m3

1 dyne/cm2= 10-5 N10-4 m2=0.1 Pa

W=8000 0.1=800 J

Answer: (1)

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Ques. 2JEE Main 2024, 27 January (Morning Shift)

0.08 kg air is heated at constant volume through 5 . The specific heat of air at constant volume is 0.17 kcal/kg C and J=4.18 joule/cal. The change in its internal energy is approximately.

  1. 318 J
  2. 298 J
  3. 284 J
  4. 142 J
Ques. 3JEE Main 2024, 27 January (Evening Shift)

During an adiabatic process, the pressure of a gas is found to be proportional to the cube of its absolute temperature. The ratio of CpCv for the gas is :

  1. 75
  2. 32
  3. 97
  4. 53

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