A thermodynamic system is taken from an original state A to an intermediate state B by a linear process as shown in the figure. Its volume is then reduced to the original value from B to C by an isobaric process. The total work done by the gas from A to B and B to C would be : [figure]
- 800 J
- 2200 J
- 33800 J
- 1200 J
Answer
(1) 800 J
Solution
[figure]
WAB+WBC = area of triangle ABC
WAB (expansion) = area under AB (+); WBC (compression) = - area under BC.
W= 12 (7-3) m3 (8000-4000) dyne/cm2
=8000 dyne cm-2 m3
1 dyne/cm2= 10-5 N10-4 m2=0.1 Pa
W=8000 0.1=800 J
Answer: (1)