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Waves

JEE Main 2024 (Online) 31st January Morning ShiftMCQEasy📈 Topic in 17% papers+4−1
Ques. 1JEE Main 2024, 31 January (Morning Shift)

The fundamental frequency of a closed organ pipe is equal to the first overtone frequency of an open organ pipe. If length of the open pipe is 60 cm, the length of the closed pipe will be:

  1. 15 cm
  2. 60 cm
  3. 45 cm
  4. 30 cm

Answer

(1) 15 cm

Solution

Closed pipe, fundamental: fc= v4Lc

Open pipe, first overtone (2nd harmonic): fo=2 v2Lo= vLo

fc=fo v4Lc= vLo Lc= Lo4

= 604=15 cm

Answer: (1)

Keep practising — Waves

Ques. 2JEE Main 2024, 31 January (Evening Shift)

The speed of sound in oxygen at S.T.P. will be approximately: (given, R=8.3 J mol-1 K-1, =1.4)

  1. 341 m/s
  2. 333 m/s
  3. 325 m/s
  4. 315 m/s
Ques. 3JEE Main 2024, 30 January (Morning Shift)

In a closed organ pipe, the frequency of fundamental note is 30 Hz. A certain amount of water is now poured in the organ pipe so that the fundamental frequency is increased to 110 Hz. If the organ pipe has a cross-sectional area of 2 cm2, the amount of water poured in the organ tube is g. (Take speed of sound in air is 330 m/s)

Ques. 4JEE Main 2024, 30 January (Evening Shift)

A point source is emitting sound waves of intensity 16 10-8 W m-2 at the origin. The difference in intensity (magnitude only) at two points located at distances of 2 m and 4 m from the origin respectively will be 10-8 W m-2.

Ques. 5JEE Main 2024, 27 January (Evening Shift)

A closed organ pipe 150 cm long gives 7 beats per second with an open organ pipe of length 350 cm, both vibrating in fundamental mode. The velocity of sound is m/s.

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