If kinetic energy of a body is increased by 300% then percentage change in momentum will be :
- 100%
- 150%
- 265%
- 73.2%
Answer
(1) 100%
Solution
p = 2mK p K
Kinetic energy increased by 300% K' = K + 3K = 4K
p' = 4 p = 2p
Percentage change in momentum = 2p - pp 100 = 100\%
Answer: (1)