Two sound waves with wavelengths 5.0 m and 5.5 m respectively, each propagate in a gas with velocity 330 m/s. We expect the following number of beats per second.
- 6
- 12
- 0
- 1
Answer
(1) 6
Solution
1 = v 1 = 3305.0 = 66 Hz
2 = v 2 = 3305.5 = 60 Hz
Beats per second = 1 - 2 = 66 - 60 = 6
Answer: (1)