A body of mass 2 kg moving with velocity of vin = 3 i + 4 j m s-1 enters into a constant force field of 6 N directed along positive z-axis. If the body remains in the field for a period of 53 seconds, then velocity of the body when it emerges from the force field is:
- 3 i + 4 j + 5 k
- 4 i + 3 j + 5 k
- 3 i + 4 j - 5 k
- 3 i + 4 j + 5 k
Answer
(4) 3 i + 4 j + 5 k
Solution
Acceleration: a = Fm = 6 k2 = 3 k m s-2
The force has no x- or y-component, so vx = 3 and vy = 4 stay unchanged.
vz = 0 + a t = 3 53 = 5 m s-1
v = 3 i + 4 j + 5 k m s-1
Answer: (4)