The resistance of each arm of the Wheatstone's bridge is 10 ohm. A resistance of 10 ohm is connected in series with a galvanometer then the equivalent resistance across the battery will be
- 10 ohm
- 15 ohm
- 20 ohm
- 40 ohm
Answer
(1) 10 ohm
Solution
All four arms are equal (10 each), so PQ = RS and the bridge is balanced.
No current flows through the galvanometer branch, so it (with its series 10 ) can be removed.
Remaining: two branches of (10 + 10) = 20 each in parallel.
Req = 20 2020 + 20
= 10
Answer: (1)