In a vernier callipers, 50 vernier scale divisions are equal to 48 main scale divisions. If one main scale division = 0.05 mm, then the least count of the vernier callipers is mm.
- 0.002
- 0.02
- 0.05
- 0.005
Answer
(1) 0.002
Solution
50 VSD = 48 MSD 1 VSD = 4850 MSD
Least count = 1 MSD - 1 VSD = (1 - 4850 )MSD
LC = 250 0.05 mm
LC = 0.002 mm
Answer: (1)