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Kinetic Theory · Question 27

AIPMT 2008MCQEasy📈 Topic in 25% papers+4−1
1

At 10 the value of the density of a fixed mass of an ideal gas divided by its pressure is x. At 110 this ratio is

  1. 10110x
  2. 283383x
  3. x
  4. 383283x

Answer

(2) 283383x

Solution

For an ideal gas, PV = mM0RT, where M0 is the molar mass

P = M0RT, i.e. P 1T

T1 = 10 + 273 = 283 K, T2 = 110 + 273 = 383 K

( /P)2x = T1T2 = 283383

( /P)2 = 283383x

Answer: (2)

AIPMT 2008

Keep practising — Kinetic Theory

2

The equation of state for 5 g of oxygen at a pressure P and temperature T, when occupying a volume V, will be (where R is the gas constant)

  1. PV = (5/32)RT
  2. PV = 5RT
  3. PV = (5/2)RT
  4. PV = (5/16)RT
AIPMT 2004
3

To find out degrees of freedom, the expression is

  1. f = 2 - 1
  2. f = + 12
  3. f = 2 + 1
  4. f = 1 + 1
AIPMT 2000

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