Thermodynamics (Physics) · Question 29

Identify the characteristics of an adiabatic process in a monoatomic gas. Choose the correct answer from the options given below :

1. (B), (D) only
2. (B), (E) only
3. (A), (C), (E) only
4. (A), (C), (D) only

Answer

(2) (B), (E) only

Solution

Adiabatic process: Q = 0, PV = constant, TV - 1 = constant; monoatomic gas = 53

(A) U = nCV T 0 (temperature changes). Incorrect.

(B) First law with Q = 0: U = -Wby gas = Won gas, so the work done equals the change in internal energy (in magnitude). Correct.

(C) TV - 1 = TV2/3 = constant, not TV. Incorrect.

(D) PV = constant; PV = constant holds only for an isothermal process. Incorrect.

(E) W = nR(T1 - T2) - 1 = - 32nR(T2 - T1) W (T2 - T1). Correct.

(B), (E) only

Answer: (2)