Current passing through a wire as function of time is given as I(t) = 0.02t + 0.01 A. The charge that will flow through the wire from t = 1 s to t = 2 s is
- 0.02 C
- 0.07 C
- 0.06 C
- 0.04 C
Answer
(4) 0.04 C
Solution
I = dqdt q = 12 I dt
q = 12 (0.02t + 0.01) dt = [0.01t2 + 0.01t ]12
= 0.01(4 - 1) + 0.01(2 - 1)
= 0.03 + 0.01 = 0.04 C
Answer: (4)