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In the given figure, the charge stored in 6 capacitor, when points A and B are joined by a connecting wire is . [figure]
36
At steady state no current flows through a capacitor (open branch). With A and B joined:
[figure]
I= 96+3=1 A (9 V → 6 Ω → A–B → 3 Ω → ground)
VA=VB=9-1 6=3 V
p.d. across 6 =9-3=6 V
Q=CV=6 6 V=36
Answer: 36
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