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Moving Charges and Magnetism · Question 88

AIPMT 2001MCQEasy📈 Topic in 12% papers+4−1
1

An electron having mass m and kinetic energy E enters a uniform magnetic field B perpendicularly, then its frequency will be

  1. eEqvB
  2. 2 meB
  3. eB2 m
  4. 2meBE

Answer

(3) eB2 m

Solution

The magnetic force provides the centripetal force:

mv2r = evB

= vr = eBm

f = 2 = eB2 m

The frequency does not depend on the speed (or kinetic energy E) of the electron.

Answer: (3)

AIPMT 2001

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2

In Thomson mass spectrograph, if E B, then the velocity of electron beam will be

  1. | E|| B|
  2. E B
  3. | B|| E|
  4. E2 B2
AIPMT 2001
3

The magnetic field at centre, P will be [figure]

  1. 04
  2. 0
  3. 02
  4. 4 0
AIPMT 2000

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