If 0 and 0 are the permeability and permittivity of free space, respectively, then the dimension of ( 1 0 0 ) is :
- T2/L
- L2/T2
- T2/L2
- L/T2
Answer
(2) L2/T2
Solution
Speed of light in free space: c = 1 0 0
1 0 0 = c2
[ 1 0 0] = [ LT-1]2 = L2/T2
Answer: (2)