The binding energies for the following nuclear reactions are expressed in MeV. 2He3 + 0n1 2He4 + 20 MeV 2He4 + 0n1 2He5 - 0.9 MeV If X3, X4, X5 denote the stability of 2He3, 2He4 and 2He5, respectively, then the correct order is :
- X4 > X5 > X3
- X4 < X5 < X3
- X4 > X5 < X3
- X4 = X5 = X3
Answer
(1) X4 > X5 > X3
Solution
Stability of a nucleus is measured by its binding energy per nucleon.
Reaction 1 releases 20 MeV: BE(He4) = BE(He3) + 20 MeV
Reaction 2 absorbs 0.9 MeV: BE(He5) = BE(He4) - 0.9 MeV
Adding a neutron to He4 lowers the total binding energy, BEA of He5 is less than that of He4 X4 > X5
From the two equations: BE(He5) = BE(He3) + 19.1 MeV, i.e. He5 gains about 19 MeV for only 2 extra nucleons.
Taking BE(He4) = 28.3 MeV: BE(He3) = 8.3 MeV, BE(He5) = 27.4 MeV
BEA: He3: 8.33 2.8 MeV, He4: 28.34 7.1 MeV, He5: 27.45 5.5 MeV
X5 > X3
X4 > X5 > X3
Answer: (1)