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Motion in a Straight Line · Question 44

AIPMT 2001MCQEasy📈 Topic in 38% papers+4−1
1

A particle is thrown vertically upward. Its velocity at half of the height is 10 m/s, then the maximum height attained by it is (g = 10 m/s2)

  1. 8 m
  2. 20 m
  3. 10 m
  4. 16 m

Answer

(3) 10 m

Solution

Let the maximum height be H. From height H2 (speed v = 10 m/s) to the top (speed 0):

0 = v2 - 2g ( H2 )

v2 = gH

H = v2g = 10010 = 10 m

Answer: (3)

AIPMT 2001

Keep practising — Motion in a Straight Line

2

Motion of a particle is given by equation s = (3t3 + 7t2 + 14t + 8) m. The value of acceleration of the particle at t = 1 s is

  1. 10 m/s2
  2. 32 m/s2
  3. 23 m/s2
  4. 16 m/s2
AIPMT 2000

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