Two rotating bodies A and B of masses m and 2m with moments of inertia IA and IB (IB > IA) have equal kinetic energy of rotation. If LA and LB be their angular momenta respectively, then
- LA = LB2
- LA = 2LB
- LB > LA
- LA > LB
Answer
(3) LB > LA
Solution
Kinetic energy of rotation, K = 12I 2 = L22I
L = 2IK
K is the same for both, L I
IB > IA LB > LA
Answer: (3)