The height (in m) of the liquid in left chamber at t=500 s is:
Answer
1.25
Solution
Key idea: efflux speed through the hole depends on the level difference x=h1-h2: v= 2gx; each chamber has base area A=1 1=1 m2 and h1+h2=2.
dh1dt=- avA, dh2dt=+ avA dxdt=-2a 2gx.
d xdt=-a 2g=- 10 10-4 20=- 2 10-3 m1/2s-1.
x= 2- 2 10-3 500= 22 x=0.5 m.
h1= 2+x2=1.25 m (and h2=0.75 m).
Answer: 1.25