A deuteron is bombarded on 8O16 nucleus, then an -particle is emitted. The product nucleus is
- 7N13
- 5B10
- 4Be9
- 7N14
Answer
(4) 7N14
Solution
8O16 + 1H2 ZXA + 2He4
Conservation of mass number:
16 + 2 = A + 4 ⇒ A = 14
Conservation of charge number:
8 + 1 = Z + 2 ⇒ Z = 7
∴ The product nucleus is 7N14.
Answer: (4)