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Units and Measurements · Question 4

JEE Advanced 2025 Paper 2MCQMedium📈 Topic in 33% papers+4−1
1

A temperature difference can generate e.m.f. in some materials. Let S be the e.m.f. produced per unit temperature difference between the ends of a wire, the electrical conductivity and the thermal conductivity of the material of the wire. Taking M, L, T, I and K as dimensions of mass, length, time, current and temperature, respectively, the dimensional formula of the quantity Z= S2 is:

  1. [M0L0T0I0K0]
  2. [M0L0T0I0K-1]
  3. [M1L2T-2I-1K-1]
  4. [M1L2T-4I-1K-1]

Answer

(2) [M0L0T0I0K-1]

Solution

Write each quantity in base dimensions.

[S]= [V][K]=[ML2T-3I-1K-1], so [S2]=[M2L4T-6I-2K-2]

[ ]= 1[ ]=[M-1L-3T3I2]

[ ]= [power][L][K]=[MLT-3K-1]

[Z]= [M2L4T-6I-2K-2][M-1L-3T3I2][MLT-3K-1]=[M0L0T0I0K-1]

Answer: (B)

JEE Advanced 2025 Paper 2

Keep practising — Units and Measurements

2

A dimensionless quantity is constructed in terms of electronic charge e, permittivity of free space 0, Planck's constant h, and speed of light c. If the dimensionless quantity is written as e 0 h c and n is a non-zero integer, then ( , , , ) is given by

  1. (2n,-n,-n,-n)
  2. (n,-n,-2n,-n)
  3. (n,-n,-n,-2n)
  4. (2n,-n,-2n,-2n)
JEE Advanced 2024 Paper 1
3

The dimensions of a cone are measured using a scale with a least count of 2 mm. The diameter of the base and the height are both measured to be 20.0 cm. The maximum percentage error in the determination of the volume is .

JEE Advanced 2024 Paper 2

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