Two equilateral-triangular prisms P1 and P2 are kept with their sides parallel to each other, in vacuum, as shown in the figure. A light ray enters prism P1 at an angle of incidence such that the outgoing ray undergoes minimum deviation in prism P2. If the respective refractive indices of P1 and P2 are 32 and 3, then = -1 [ 32 ( ) ], where the value of is . [figure]
Answer
12
Solution
Minimum deviation in P2 (A = 60 ): refraction angle inside = 30 ; i = 3 30 = 32 i = 60 .
The exit face of P1 is parallel to the entry face of P2, so the ray leaves P1 at e = 60 .
At exit face of P1: 32 r2 = 60 r2 = 1 2, r2 = 45 .
r1 = A - r2 = 60 - 45 = 15 = 12
At entry: = 32 12 = 12
Answer: 12