A capacitor of capacity C1 charged up to V volt and then connected to an uncharged capacitor of capacity C2. The final potential difference across each will be
- C1VC1+C2
- C2VC1+C2
- (1- C2C1 )V
- (1+ C2C1 )V
Answer
(1) C1VC1+C2
Solution
Initial charge on C1: Q = C1V
On connecting, the charge is shared until both are at the same potential V' (the capacitors are in parallel).
Conservation of charge:
C1V = (C1 + C2)V'
∴ V' = C1VC1+C2
Answer: (1)