If the wavelength of the first member of Lyman series of hydrogen is . The wavelength of the second member will be
- 275
- 527
- 2732
- 3227
Answer
(3) 2732
Solution
Lyman series: 1 =R ( 112- 1n2 )
First member (n=2): 1 = 3R4; second member (n=3): 1 '= 8R9
' = 3/48/9= 2732
'= 2732
Answer: (3)