A photon and an electron, each of 20 eV energy, move in free space. The ratio of linear momentum of electron pe to that of photon pPh, pepPh is: [Take speed of light = 3 108 m s-1, charge of electron = -1.6 10-19 C and mass of electron = 9 10-31 kg]
- 275
- 2450
- 1250
- 225
Answer
(4) 225
Solution
For a photon of energy E, momentum is:
pPh = Ec
For an electron of energy E, momentum is:
pe = 2mE
Taking their ratio:
pepPh = 2mEE/c = c 2mE
Given E = 20 eV = 20 1.6 10-19 J = 3.2 10-18 J:
pepPh = (3 108) 2 9 10-313.2 10-18 = (3 108) 5.625 10-13 = (3 108)(7.5 10-7) = 225
Answer: (4)