A particle moving in a straight line covers half the distance with speed 6 m/s. The other half is covered in two equal time intervals with speeds 9 m/s and 15 m/s respectively. The average speed of the particle during the motion is :
- 9.2 m/s
- 8.8 m/s
- 10 m/s
- 8 m/s
Answer
(4) 8 m/s
Solution
[figure]
Second half (BD), two equal times t: s = 9t + 15t = 24t
First half (AB): s = 6t1 = 24t t1 = 4t
Average speed = total distancetotal time = 2st1 + 2t = 48t6t
= 8 m/s
Answer: (4)