Two identical small bar magnets each of dipole moment 3 5 J/T are placed at a center to center separation of 10 cm, with their axes perpendicular to each other as shown in figure. The value of magnetic field at the point P midway between the magnets is 10-3 T. The value of is . ( 0=4 10-7 Tm/A) [figure]
Answer
12
Solution
P is at r=5 cm =0.05 m from the centre of each magnet.
04 Mr3=10-7 3 5(0.05)3
=10-7 3 51.25 10-4=2.4 5 10-3 T
Horizontal magnet: P is on its axial line
B1= 04 2Mr3=4.8 5 10-3 T, along its moment (S N, to the right)
Vertical magnet: P is on its equatorial line
B2= 04 Mr3=2.4 5 10-3 T, opposite to its moment (upward)
[figure]
B1 B2 B= B12+B22=2.4 5 10-3 22+12
=2.4 5 5 10-3=12 10-3 T
=12
Answer: 12