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Work, Energy and Power

JEE Main 2025 (Online) 22nd January Morning ShiftMCQMedium📈 Topic in 16% papers+4−1
Ques. 1JEE Main 2025, 22 January (Morning Shift)

A bob of mass m is suspended at a point O by a light string of length l and left to perform vertical motion (circular) as shown in figure. Initially, by applying horizontal velocity v0 at the point ' A ', the string becomes slack when the bob reaches at the point ' D '. The ratio of the kinetic energy of the bob at the points B and C is . [figure]

  1. 4
  2. 1
  3. 2
  4. 3

Answer

(3) 2

Solution

At D the string goes slack: T=0 mg= mvD2l, so KD= 12mgl.

[figure]

Depth below D: C = l2, B = 3l2, and K=KD+mg (depth)

KC= 12mgl+ 12mgl=mgl

KB= 12mgl+ 32mgl=2mgl

KBKC=2

Answer: (3)

Keep practising — Work, Energy and Power

Ques. 2JEE Main 2025, 22 January (Evening Shift)

A body of mass 100 g is moving in circular path of radius 2 m on vertical plane as shown in figure. The velocity of the body at point A is 10 m/s. The ratio of its kinetic energies at point B and C is : [figure] (Take acceleration due to gravity as 10 m/s2)

  1. 3- 22
  2. 2+ 33
  3. 2+ 23
  4. 3+ 32
Ques. 3JEE Main 2025, 22 January (Evening Shift)

A ball of mass 100 g is projected with velocity 20 m/s at 60 with horizontal. The decrease in kinetic energy of the ball during the motion from point of projection to highest point is

  1. 20 J
  2. 5 J
  3. 15 J
  4. zero
Ques. 4JEE Main 2025, 22 January (Evening Shift)

A force F=2 i+b j+ k is applied on a particle and it undergoes a displacement i-2 j- k. What will be the value of b, if work done on the particle is zero.

  1. 13
  2. 12
  3. 0
  4. 2

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