The total radiant energy per unit area, normal to the direction of incidence, received at a distance R from the centre of a star of radius r, whose outer surface radiates as a black body at a temperature T K is given by
- 2T4R2
- 2T44 2
- 2T4R4
- 4 2T4R2
Answer
(1) 2T4R2
Solution
Power radiated by the star (Stefan's law):
P = 4 4 2
This spreads over a sphere of radius R, so energy received per unit area per second:
E = P4 R2 = 4 4 24 2 = 2T4R2
Answer: (1)