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Alternating Current · Question 16

JEE Main 2025 (Online) 3rd April Evening ShiftMCQEasy📈 Topic in 13% papers+4−1
1

An electric bulb rated as 100 W - 220 V is connected to an ac source of rms voltage 220 V. The peak value of current through the bulb is:

  1. 0.32 A
  2. 0.64 A
  3. 0.45 A
  4. 2.2 A

Answer

(2) 0.64 A

Solution

At rated voltage the bulb consumes its rated power: P = Vrms Irms

Irms = 100220 = 0.4545 A

I0 = 2 Irms = 1.414 0.4545

I0 0.64 A

Answer: (2)

JEE Main 2025 (Online) 3rd April Evening Shift

Keep practising — Alternating Current

2

Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). In the light of the above statements, choose the most appropriate answer from the options given below :

  1. (A) is true but (R) is false
  2. Both (A) and (R) are true and (R) is the correct explanation of (A).
  3. Both (A) and (R) are true but (R) is not the correct explanation of (A)
  4. (A) is false but (R) is true
JEE Main 2025 (Online) 29th January Morning Shift

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