[figure] A wheel of radius 0.2 m rotates freely about its center when a string that is wrapped over its rim is pulled by a force of 10 N as shown in figure. The established torque produces an angular acceleration of 2 rad/s2. Moment of inertia of the wheel is kg m2. (Acceleration due to gravity = 10 m/s2)
Answer
1
Solution
The string leaves the rim tangentially, so the force acts at a perpendicular distance r from the axis.
Torque: = Fr = 10 0.2 = 2 N m
= I I = = 22
I = 1 kg m2
Answer: 1