In the Young's double slit experiment the intensity produced by each one of the individual slits is Io. The distance between two slits is 2 mm. The distance of screen from slits is 10 m. The wavelength of light is 6000 . The intensity of light on the screen in front of one of the slits is
- Io2
- Io
- 2Io
- 4Io
Answer
(2) Io
Solution
Point in front of one slit: y = d2 = 1 mm
Path difference x = ydD = (1 10-3)(2 10-3)10 = 2 10-7 m
= 6000 = 6 10-7 m
Phase difference = 2 x = 2 6 10-7 2 10-7 = 2 3
I = 4Io 2 2 = 4Io 2 60 = 4Io 14 = Io
Answer: (2)