Two rods A and B of different materials are welded together as shown in figure. Their thermal conductivities are K1 and K2. The thermal conductivity of the composite will be [figure]
- 3(K1 + K2)2
- K1 + K2
- 2 (K1 + K2)
- K1 + K22
Answer
(4) K1 + K22
Solution
Both rods have the same length d and equal cross-sectional area A and lie between the same ends (T1, T2) parallel combination.
H = H1 + H2
K(2A)(T1 - T2)d = K1A(T1 - T2)d + K2A(T1 - T2)d
K = K1 + K22
Answer: (4)