A conducting solid sphere of radius R and mass M carries a charge Q. The sphere is rotating about an axis passing through its center with a uniform angular speed . The ratio of the magnitudes of the magnetic dipole moment to the angular momentum about the same axis is given as Q2M. The value of is
Answer
1.65 to 1.67
Solution
Charge on a conductor resides on its surface (shell), while mass is spread through the solid sphere.
Rotating charged shell: = Q R23
Solid sphere: L= 25MR2
L= Q/32M/5= 5Q6M= 53 Q2M
= 53 1.67
Answer: 1.67