The speed of a projectile at its maximum height is half of its initial speed. The angle of projection is
- 60
- 15
- 30
- 45
Answer
(1) 60
Solution
At the maximum height the velocity is horizontal: v = u
Given u = u2
⇒ = 12
∴ = 60
Answer: (1)
The speed of a projectile at its maximum height is half of its initial speed. The angle of projection is
(1) 60
At the maximum height the velocity is horizontal: v = u
Given u = u2
⇒ = 12
∴ = 60
Answer: (1)
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