A concave mirror produces an image of an object such that the distance between the object and image is 20 cm. If the magnification of the image is -3, then the magnitude of the radius of curvature of the mirror is :
- 3.75 cm
- 15 cm
- 7.5 cm
- 30 cm
Answer
(2) 15 cm
Solution
m = - vu = -3 v = 3u (both on the object side, real image)
Let u = -x v = -3x
Distance between object and image: 3x - x = 20 x = 10 cm
u = -10 cm, v = -30 cm
1f = 1v + 1u = - 130 - 110 = - 430
f = -7.5 cm
|R| = 2|f| = 15 cm
Answer: (2)